Python Pass Gen (Similar to random.org)

tnxbt · 19-10-2017, 10:47 PM

For anyone starting to learn python, have a change around with this which will help learn some basic validation and variable handling. I made this just now and commented on lines to help explain whats going on, it's not meant to be super efficient, I only quickly made this to show something you can do in python.

Code:
import os, string, random 
 
 length = input("Length : ")# String input
 while length.isnumeric == False:# While the input is not numbers ask again until is. 
 length = input("Length : ")
 length = int(length)# Turns the variable into an integer
 
 amount = input("Amount : ")# While the input is not numbers ask again until is. 
 while amount.isnumeric == False:
 amount = input("Amount : ")
 amount = int(amount)# Turns the variable into an integer
 
 for m in range(amount):#Creates a new one until reaches amount wanted
 characters = string.ascii_letters + string.digits + "()*%" #includes all letters and digits, but for stronger pass added symbols
 random.seed = (os.urandom(512)) # 512 is overkill, only really need 64 or less. To put it into easy terms, makes it more random.
 print ("".join(
 random.choice(characters) # Randomly selects one of the characters from the variable above
 for i in range(length)# adds a random letter until reaches length
 )
 )

Making a program and need help with a problem? PM me.

Python Pass Gen (Similar to random.org)

Submitted by tnxbt, 19-10-2017, 10:47 PM, Thread ID: 52052