200 Giveaway

15-11-2015, 06:05 PM

Gnar Wrote:

15-11-2015, 09:10 AM

education Wrote: a3 + b3 + c3 = 33


Lets pick numbers that might work. This is called a trial and error. We need to pick cubic numbers that add up to 33. the number zero will not give us any results. So the three numbers must be nonzero.

1 + 8 + 27 = 36


This sum is close to 36.

-2 + 8 + 27 = 33

3(-2)3 + 23 + 33 = 33


Therefore,

a = 3(-2) = -1.2299

b = 2

c = 3

I'm sorry to say but your answer is wrong.

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15-11-2015, 05:57 PM

NSA Wrote:

15-11-2015, 09:10 AM

education Wrote: a3 + b3 + c3 = 33


Lets pick numbers that might work. This is called a trial and error. We need to pick cubic numbers that add up to 33. the number zero will not give us any results. So the three numbers must be nonzero.

1 + 8 + 27 = 36


This sum is close to 36.

-2 + 8 + 27 = 33

3(-2)3 + 23 + 33 = 33


Therefore,

a = 3(-2) = -1.2299

b = 2

c = 3

You put the numbers wrongly in the calculator. It must be like this:(a)^3+(b)^3+©^3=33 not a^3+b^3+^3=33.

What calculator do you use, it looks cool