15-11-2015, 06:22 PMNSA Wrote:15-11-2015, 06:05 PMGnar Wrote:15-11-2015, 09:10 AMeducation Wrote: a3 + b3 + c3 = 33
Lets pick numbers that might work. This is called a trial and error. We need to pick cubic numbers that add up to 33. the number zero will not give us any results. So the three numbers must be nonzero.
1 + 8 + 27 = 36
This sum is close to 36.
-2 + 8 + 27 = 33
3(-2)3 + 23 + 33 = 33
Therefore,
a = 3(-2) = -1.2299
b = 2
c = 3
I'm sorry to say but your answer is wrong.
15-11-2015, 05:57 PMNSA Wrote:15-11-2015, 09:10 AMeducation Wrote: a3 + b3 + c3 = 33
Lets pick numbers that might work. This is called a trial and error. We need to pick cubic numbers that add up to 33. the number zero will not give us any results. So the three numbers must be nonzero.
1 + 8 + 27 = 36
This sum is close to 36.
-2 + 8 + 27 = 33
3(-2)3 + 23 + 33 = 33
Therefore,
a = 3(-2) = -1.2299
b = 2
c = 3
You put the numbers wrongly in the calculator. It must be like this:(a)^3+(b)^3+©^3=33 not a^3+b^3+^3=33.
What calculator do you use, it looks cool
Here is the calculatorhttp://[disallowed url shortening site]/IqT6zt
Just kidding,
here it is:http://web2.0calc.com/
here it is:http://web2.0calc.com/